Question

Find the equation of the perpendicular bisector of the line segment obtained on joining the points (6, -3) and (0, 3).

Answer 1

Let A = (6, -3) and B = (0, 3).

We know the perpendicular bisector of a line is perpendicular to the line and it bisects the line, that it, it passes through the mid-point of the line.

Co-ordinates of the mid-point of AB are

Thus, the required line passes through (3, 0).

Slope of AB =

Slope of the required line =

Thus, the equation of the required line is given by:

y - y₁ = m(x - x₁)

y - 0 = 1(x - 3)

y = x - 3