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Byju's Answer
Standard XII
Mathematics
Equation of a Plane Passing through Three Points
Find the equa...
Question
Find the equation of the plane passing through the point (1,-2,1) and perpendicular to the line joining the points A(3, 2,1) and B(1, 4, 2).
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Solution
The
equation
of
a
plane
passing
through
the
point
1
,
-
2
,
1
is
,
a
x
-
1
+
b
y
+
2
+
c
z
-
1
=
0
.
.
.
.
.
.
1
Here
,
a
,
b
,
c
are
the
direction
ratios
of
the
normal
to
the
plane
.
Equation
of
the
line
joining
the
points
A
3
,
2
,
1
and
B
1
,
4
,
2
is
,
x
-
3
1
-
3
=
y
-
2
4
-
2
=
z
-
1
2
-
1
⇒
x
-
3
-
2
=
y
-
2
2
=
z
-
1
1
.
.
.
.
.
.
.
2
Now
,
direction
ratios
of
line
AB
are
:
a
1
,
b
1
,
c
1
=
-
2
,
2
,
1
Since
,
the
plane
1
is
⊥
to
the
line
AB
,
then
a
,
b
,
c
≡
a
1
,
b
1
,
c
1
=
-
2
,
2
,
1
Putting
the
values
of
a
,
b
and
c
in
1
,
we
get
-
2
x
-
1
+
2
y
+
2
+
1
z
-
1
=
0
⇒
-
2
x
+
2
+
2
y
+
4
+
z
-
1
=
0
⇒
-
2
x
+
2
y
+
z
+
5
=
0
⇒
2
x
-
2
y
-
z
-
5
=
0
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