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Question

Find the equation of the plane through the line x+1/-3 = y-3/2 = z+2/1 and the point (0,7,-7). Show also that the line x= 7-y/3 = z+7/2 lies on this plane

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Solution

Dear student,
We know that equation of a plane passing through the point x1,y1,z1 and having direction ratiosof the normal to the plane as a,b,c isax-x1 + by-y1 + cz-z1 = 0Now, equation of the plane passing through 0,7,-7 and having direction ratiosof the normal to the plane as a,b,c isax-0 + by-7+cz+7 = 0 ........1Now, the given equation of the line isx+1-3 = y-32 = z+21 ......2Now, the line 2 passes through -1,3,-2 and having direction ratios -3,2,1.Since the plane 1 contains the line 2, then plane 1 must pass through -1,3,-2.Now, from 1, we get a-1-0+b3-7+c-2+7 = 0-a-4b+5c = 0a+4b-5c = 0 .......3Since plane 1 contains the line 2, line is parallel to the plane.Now, -3a + 2b + c = 0 .........4Solving 3 and 4 by cross multiplication, a4+10 = b15-1 = c2+12Let a14 = b114 = c14 = ka = b = c = kNow, from 1, we getkx-0+ky-7+kz+7 = 0x+y+z = 0
​​​​​​Regards

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