Find the equation of the straight line passing through the point (6, 2) and having slope -3.

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Solution

$Let the required equation of the line be y - y_{1} = m (x - x_{1}) Now, m = s l o p e = - 3 (x_{1} y_{1}) = (6, 2) ∴ y - y_{1} = m (x - x_{1}) \Rightarrow y - 2 = - 3 (x - 6) \Rightarrow y - 2 = - 3 x + 18 \Rightarrow 3 x + y = + 20 \Rightarrow 3 x + y - 20 = 0 ∴ The equation of the given line is 3x + y - 20 = 0$

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