Question

Find the equation of the straight line passing through the point (6, 2) and having slope -3.

Answer 1

$\text{Let the required equation of the line be}y-y_1=m(x-x_1)\text{Now,}m=slope=-3\left(x_1{y}_1\right)=(6,2)\therefore y-y_1=m(x-x_1)\Rightarrow y-2=-3(x-6)\Rightarrow y-2=-3x+18\Rightarrow 3x+y=+20\Rightarrow 3x+y-20=0\therefore \text{The equation of the given line is 3x + y - 20 = 0}$