Question

Find the equation of the straight line passing through the point (6, 2) and having slope − 3.

Answer 1

Here, $m=-3,x_1=6\mathrm{and}{y}_1=2$

Substituting these values in $y-y_1=m\left(x-x_1\right)$, we get,

$$\begin{gathered} y-2=-3\left(x-6\right) \\ \Rightarrow y-2=-3x+18 \\ \Rightarrow 3x+y-20=0 \end{gathered}$$

Hence, the equation of the required line is $3x+y-20=0$