Question

Find the equation of the straight line whose slope is $\frac{2}{3}$ and passing through $(5,-4)$.

Answer 1

Equation of a straight line is $y-y_1=m(x-x_1)$

where $x_1=5,y_1=-4$ and the slope $m=\frac{2}{3}$

$\therefore$ Equation of the straight line is $y-(-4)=\frac{2}{3}(x-5)$

$\Rightarrow y+4=\frac{2}{3}(x-5)$

$\Rightarrow 3y+12=2x-10$

or $2x-3y-22=0$ is the required equation of the straight line.