Find the equilibrium constant for the reaction- Fe2- - Ce4- Fe3- - Ce3-Given- EoCe4-Ce3- - 1-44 V- EoFe3- - Fe2- - 0-68 V-

The correct option is A 7.6 × 10^12 E^o_cell = 0.059/1 log_10 K_c E^o_cell = E^o_OP_Fe^2+ /Fe^3+ + E^o_RP_Ce^4+ / Ce^3+ E^o_cell= 0.68 +1.4 ...

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Equilibrium Constant from Nernst Equation

Find the equi...

Question

Find the equilibrium constant for the reaction, $F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}$ .

[Given: $E_{C e^{4 +} / C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{o} = 0.68 V$ ]

7.6 \times 10^{12}

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5.4 \times 10^{12}

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3.3 \times 10^{12}

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None of the above

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Solution

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F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{0} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{0} = 0.68 V]

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{{C e}^{4 +} / C e^{3 +}}^{\circ} = 1.44 V; E_{F e^{2 +} / F e^{3 +}}^{\circ} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} | C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} | F e^{2 +}}^{o} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ C e^{3 +} + F e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{\circ} = 1.44 V

E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.68 V

\frac{2.303 R T}{F} = 0.06

25^{o} C, l o g 4.68 = 0.67

F e^{2 +} + C e^{4 +} | F e^{3 +} + C e^{3 +}

E^{0} C e^{4 +} / C e^{3 +} = 1.44

E^{0} F e^{3 +} / F e^{2 +} = 0.68 V]

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