Find the equivalent resistance between A & B in the given circuit.
The resistors on the right most sides are in series
So, they can be replaced with their net resistance which will be 2 + 2 + 2 = 6 Ω which is in parallel with 3 Ω.
Resistors 6 Ω and 3 Ω are in parallel, which will be 2 Ω
So, the circuit reduces to
Repeating the same process, we get the net resistance across AB, which will be 6 Ω