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Equivalent Mass

Find the equi...

Question

Find the equivalent weight of thiosulphate ion from the following reaction:
$2 S_{2} O_{3}^{2 -} (R e d u c i n g a g e n t) \to S_{4} O_{6}^{2 -} + 2 e^{-}$

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\frac{M}{2}

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Solution

The correct option is A M
The given equation is,
$2 {+ 2 S}_{2} O_{3}^{2 -} \to {+ 2.5 S}_{4} O_{6}^{2 -} + 2 e^{-}$
$n_{f} = | 2.5 - 2 | \times 2 = 1$
$Equivalent weight of S_{2} O_{3}^{2 -} = \frac{M}{1} = M$

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Similar questions

2 S_{2} O_{3}^{2 -} (R e d u c i n g a g e n t) \to S_{4} O_{6}^{2 -} + 2 e^{-}

2 S_{2} O_{3}^{2 -} (Reducing ~agent) \to S_{4} O_{6}^{2 -} + 2 e^{-}

S_{2} O_{3}^{2 -}

M

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2 S_{2} O_{3}^{2 -} (Reducing ~agent) \to S_{4} O_{6}^{2 -} + 2 e^{-}

S_{2} O_{3}^{2 -}

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I_{2} + 2 S_{2} O_{3}^{2 -} \to 2 I^{-} + S_{4} O_{6}^{2 -}

I_{2} + 2 S_{2} O_{3}^{2 -} \to 2 I^{-} + S_{4} O_{6}^{2 -}

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