Find the expansion of ${(x + y)}^{6}$ .

Open in App

Solution

Using binomial theorem
${(x + y)}^{n} = \sum_{r = 0}^{n}^{n} C_{r} x^{n - r} y^{r} {(x + y)}^{6} =_{0}^{6} C x^{6} +_{1}^{6} C x^{5} y^{1} +_{2}^{6} C x^{4} y^{2} +_{3}^{6} C x^{3} y^{3} +_{4}^{6} C x^{2} y^{4} +_{5}^{6} C x^{1} y^{5} +_{6}^{6} C x^{0} y^{6} = x^{6} + 6 x^{5} y + 15 x^{4} y^{2} + 20 x^{3} y^{3} + 15 x^{2} y^{4} + 6 x y^{5} + y^{6}$

Suggest Corrections

Similar questions

Write the general term in the expansion of (x² – y)⁶

(x + 1) (x + 4) (x + 7)

x, y, z, u > 0

\frac{x^{6} + y^{6} + 2 z^{3} + 2 u^{3}}{x y z u}

\frac{y^{6}}{343} + \frac{343}{y^{6}}

\frac{x + y}{4} - \frac{x - y}{3} = 1; \frac{x + y}{2} + \frac{x - y}{6} = 12

Join BYJU'S Learning Program