Find the expansion of
$(x - a) (x - 2 a) (x - 4 a)$

x^{3} - 7 a x^{2} + 14 a^{2} x - 8 a^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{3} + 7 a x^{2} + 14 a^{2} x - 8 a^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{3} - 7 a x^{2} - 14 a^{2} x - 8 a^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x^{3} - 7 a x^{2} + 14 a^{2} x - 8 a^{3}$
$(x - a) (x - 2 a) (x - 4 a)$

$= (x^{2} - 3 a x + 2 a^{2}) (x - 4 a)$

$= x^{3} - 4 a x^{2} - 3 a x^{2} + 12 a^{2} x + 2 a^{2} x - 8 a^{3}$

$= x^{3} - 7 a x^{2} + 14 a^{2} x - 8 a^{3}$

Suggest Corrections

Similar questions

x^{3} + 13 x^{2} + 32 x + 20

8 a^{3} - b^{3} - 12 a^{2} b + 6 a b^{2}

2 a + \frac{1}{2 a}

a \neq

Find the cube of $(2 a - 6 b)$

4 a^{2} + 8 a^{3} + 8 a^{2} + 4 a + 1

Join BYJU'S Learning Program