Find the external work done by the system inkcal, when 20 keal of heat is supplied to thesystem and the increase in the internal energyis 8400J(J=4200J/kcal)?
A
16kcal
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B
18kcal
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C
20kcal
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D
19kcal
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Solution
The correct option is B 18kcal According to 1st law of thermodynamics dU=q+W 8.4kJ=(20×4.2kJ)+W W=8.4kJ−84kJ W=−75.6kJ W=−75.6/4.2=−18kcal Work done by system is 18kcal