Find the factors of 1- 1 27 c 3-

The given question is in the familiar form. We have 1 1 27 c ^ 3 = 1 ^ 3 ( c 3 #160;) #160;^ 3 =( 1 c 3 #160;) ( 1+ c 3 + c ^ 2 9 #16 ...

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Algebraic Identities

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Question

Find the factors of $1 - \frac{1}{27} c^{3}$ .

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2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c .

2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c

{(a - \frac{1}{2} b + \frac{1}{3} c)}^{3} - a^{3} + \frac{1}{8} b^{3} - \frac{1}{27} c^{3}

{(a + 2 b - 3 c)}^{3} - a^{3} - 8 b^{3} + 27 c^{3}

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