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Algebraic Identities

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Question

Find the factors of the following expressions:

(6) 2x² + xy − 2xy² − y³

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Solution

2x² + xy − 2xy² − y³
We can factorise this expression as:
2x² + xy − 2xy² − y³
= (2x² + xy) + (− 2xy² − y³)
= x (2x + y) − y² (2x + y)
= (2x + y) (x − y²)

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