Find the following pair of linear equations by the substituting method:-

(a) 3x-y=3

9x-3y=9

b) 0.2x+0.3y=1.3

0.4x+0.5y=2.3

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Solution

The answer is correct
and the doubt you asked is
By multiplying the equation 1 by 10 and equation number 2 by 10
We can make the decimal equation to an integer equation
that is
.2x + .3y =1.3
So multiplying by 10
We get .2x×10 +.3y×10=1.3×10
It becomes
2x+3y=13
So it will be easyeafor doing the problem.

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Similar questions

0.2 x + 0.3 y = 1.3 0.4 x + 0.5 y = 2.3

Solve the equation by substitution method

0.2x+0.3y=1.3

0.4x+0.5y=2.3

\sqrt{2} x + \sqrt{3} y = 0, \sqrt{3} y - \sqrt{8} y = 0

3 x - 5 y + 1 = 0; x - y + 1 = 0

0.2 x + 0.3 y = 13, 0.4 x + 0.5 y = 2.3

(P . S)

0.2 x + 0.3 y = 1.3

0.4 x + 0.5 y = 2.3

x

y

0.2 x + 0.3 y = 1.3

0.4 x + 0.5 y = 2.3

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