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Question

Find the following product by using suitable identity
102×104

A
10578
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B
11508
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C
10608
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D
10218
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Solution

The correct option is B 10608
102×104
=(100+2)×(100+4)
Using,x2+(a+b)x+ab
=1002+(2+4)100+2(4)
=10000+600+8
=10608

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