Find the force of gravitation between two bodies of masses 1000 kg and $10^{24}$ kg, placed at a separation of 6000 km.

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Solution

$F = \frac{G M m}{R^{2}}$

$⟹ F = \frac{6.67 \times 10^{- 11} \times 10^{3} \times 10^{24}}{(6 \times 10^{6})^{2}}$

$⟹ F = 1852.8 N$

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Find the force of gravitation between two bodies of masses 1000 kg and 1024kg, placed at a separation of 6000 km.

F=GMmR2⟹F=6.67×10−11×103×1024(6×106)2⟹F=1852.8 N

Find the force of gravitation between two bodies of masses 1000 kg and $10^{24}$ kg, placed at a separation of 6000 km.

$F = \frac{G M m}{R^{2}}$

$⟹ F = \frac{6.67 \times 10^{- 11} \times 10^{3} \times 10^{24}}{(6 \times 10^{6})^{2}}$

$⟹ F = 1852.8 N$