Question

Find the G.P whose $5^{th}$ term is $48$ and $8^{th}$ term is $384$.

Answer 1

$a_5=48,a_8=384$

$a{r}^4=48,a{r}^7=384$

On solving $r^3=8⟹r=2$

Now $a(2{)}^4=48⟹a=3$

Hence the GP series will be

GP$=3,6,12,.....$