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Byju's Answer
Standard XII
Mathematics
Modulus Function
Find the gene...
Question
Find the general solution in positive integers:
5
x
−
7
y
=
3
A
x
=
7
p
−
5
and
y
=
5
p
−
4
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B
x
=
4
p
−
7
and
y
=
8
p
−
3
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C
x
=
p
−
2
and
y
=
9
p
−
6
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D
x
=
p
−
15
and
y
=
6
−
7
p
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Solution
The correct option is
C
x
=
7
p
−
5
and
y
=
5
p
−
4
Let
y
=
k
⇒
x
=
7
k
+
3
5
General solution is :
(
x
,
y
)
=
(
7
k
+
3
5
,
k
)
Now we will go by options
Let's take 1st option y=5p-4=k
⇒
x
=
7
(
5
p
−
4
)
+
3
5
⇒
x
=
7
p
−
5
∴
option 'A' is true
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0
Similar questions
Q.
Find the general solution in positive integers, and the least values of
x
and
y
which satisfy the equations:
5
x
−
7
y
=
3
.
Q.
Simplify:
(i) 2p
3
− 3p
2
+ 4p − 5 − 6p
3
+ 2p
2
− 8p − 2 + 6p + 8
(ii) 2x
2
− xy + 6x − 4y + 5xy − 4x + 6x
2
+ 3y
(iii) x
4
− 6x
3
+ 2x − 7 + 7x
3
− x + 5x
2
+ 2 − x
4
Q.
(
4
p
x
2
+
5
q
2
y
−
9
r
z
)
−
(
−
3
q
2
y
+
7
p
x
2
−
r
z
)
=
Q.
If P = 7x
2
+ 5xy
− 9y
2
, Q = 4y
2
− 3x
2
− 6xy and R = −4x
2
+ xy + 5y
2
, show that P + Q + R = 0.
Q.
From
(i) p
3
− 4 + 3p
2
, take away 5p
2
− 3p
3
+ p − 6
(ii) 7 + x − x
2
, take away 9 + x + 3x
2
+ 7x
3
(iii) 1 − 5y
2
, take away y
3
+ 7y
2
+ y + 1
(iv) x
3
− 5x
2
+ 3x + 1, take away 6x
2
− 4x
3
+ 5 + 3x
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