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Question

Find the general solution in positive integers: 5x7y=3

A
x=7p5 and y=5p4
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B
x=4p7 and y=8p3
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C
x=p2 and y=9p6
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D
x=p15 and y=67p
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Solution

The correct option is C x=7p5 and y=5p4
Let y=kx=7k+35

General solution is :(x,y)=(7k+35,k)

Now we will go by options

Let's take 1st option y=5p-4=k

x=7(5p4)+35

x=7p5

option 'A' is true

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