Question

Find the H.C.F of two consecutive numbers.

Answer 1

Let us take two consecutive numbers $5$ and $6$.

Finding the H.C.F of $5$ and $6$ by Prime Factorisation we get,

$$\begin{gathered} 5=1\times 5 \\ 6=1\times 2\times 3 \end{gathered}$$

Therefore we see that H.C.F of $5$ and $6$ is $1$

Hence, we can conclude that for any two consecutive integers, the H.C.F is always equal to $1$since they have no other common factors.