Find the HCF of $(2^{100} - 1)$ and $(2^{120} - 1) .$

2^{10} - 1

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2^{20} - 1

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None of these

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Solution

The correct option is B $2^{20} - 1$
$[2^{(g c d o f 100, 120)} - 1] = (2^{20} - 1)$

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4 x^{2} - 1

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