Question

Find the HCF of the following numbers :
$91,112,49$

Answer 1

$91,112,49$
$91=\underset{–}{1},\underset{–}{7},13,91$
$112=\underset{–}{1},2,4,\underset{–}{7},8,14,16,28,56,112$
$49=\underset{–}{1},\underset{–}{7},49$
$\therefore$ Common Factors = $1,7$
$\therefore$ H.C.F. of $91,112,49$ is $7$