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Question

Find the HCF of the following pair of polynomials:
x2xy2y2 and x2+3xy+2y2

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Solution

We know that HCF is the highest common factor.

Factorise x2xy2y2 as follows:

x2xy2y2=x22xy+xy2y2=x(x2y)+y(x2y)=(x+y)(x2y)

Now, factorise x2+3xy+2y2 as follows:

x2+3xy+2y2=x2+2xy+xy+2y2=x(x+2y)+y(x+2y)=(x+y)(x+2y)

Since the common factor between the polynomials x2xy2y2 and x2+3xy+2y2 is (x+y).

Hence, the HCF is (x+y).

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