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Question

Find the HCF of x3y2,x2y3 and x4y4

A
x3y4
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B
xy
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C
x2y2
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D
x4y4
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Solution

The correct option is C x2y2
x3y2=x3×y2
x2y3=x2×y3
and x4y4=x4×y4
HCF =x2×y2=x2y2.
Option C is correct.

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