Find the high height of a cuboidal water tank (in $m$ )if volume of the tank is $32000 d m^{3}$ and area of base is $1600 d m^{2}$ .

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Solution

Volume of the cuboidal water tank $=$ Base area $\times$ Height
$\Rightarrow$ Height $= \frac{Volume}{base area}$
$= \frac{32000 d m^{3}}{1600 d m^{2}}$
$= 20 d m$
$= 20 \times \frac{1}{10} m$
$= 2 m$

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Find the high height of a cuboidal water tank (in m )if volume of the tank is 32000 dm3 and area of base is 1600 dm2.

Volume of the cuboidal water tank = Base area × Height⇒ Height =Volumebase area =32000 dm31600 dm2=20 dm=20×110 m=2 m

Find the high height of a cuboidal water tank (in $m$ )if volume of the tank is $32000 d m^{3}$ and area of base is $1600 d m^{2}$ .

Volume of the cuboidal water tank $=$ Base area $\times$ Height
$\Rightarrow$ Height $= \frac{Volume}{base area}$
$= \frac{32000 d m^{3}}{1600 d m^{2}}$
$= 20 d m$
$= 20 \times \frac{1}{10} m$
$= 2 m$