Question

Find the inclination of the line whose slope is:​
(ii) $\sqrt{3}$

Answer 1

Given :
Slope $=\sqrt{3}$
We know , if $\tan \theta$ is the slope of line ; then the inclination of the line is $\theta$.
$\Rightarrow \tan \theta =\sqrt{3}$
$\Rightarrow \tan \theta =\tan {60}^{\circ }$
[From the trignometric table ]
$\Rightarrow \theta ={60}^{\circ }$

Hence, the inclination of the line is ${60}^{\circ }$.