You visited us 3 times! Enjoying our articles? Unlock Full Access!

Functions

Find the indi...

Question

Find the indicated term in the sequence, whose $n^{t h}$ term is: $a_{n} = \frac{n^{2}}{2^{n}}; a_{7}$ .

Open in App

Solution

Finding $a_{7}$ term of sequence.
Given, $a_{n} = \frac{n^{2}}{2^{n}}$
Substituting $n = 7$ in $a_{n}$ , we get
$a_{7} = \frac{(7)^{2}}{2^{7}}$
$\Rightarrow a_{7} = \frac{49}{128}$ .

Hence, the value of $a_{7}$ term of sequence is $\frac{49}{128}$ .

Suggest Corrections

Similar questions

Find the 7^th term in the following sequence whose n^th term is

Find the indicated terms in each of the sequences in where $n^{t h}$ terms are :

$a_{n} = \frac{n^{2}}{2^{n}}; a_{7}$

n^{t h}

a_{n} = \frac{n + 2}{2 n + 3}; a_{7}, a_{9}

a_{n} = (- 1)^{n} 2^{n + 3} (n + 1); a_{5}, a_{8}

a_{n} = 2 n^{2} - 3 n + 1; a_{5}, a_{7}

a_{n} = (- 1)^{n} (1 - n + n^{2}); a_{5}, a_{8}

n^{t h}

a_{n} = (- 1)^{n - 1} n^{3}; a_{9}

7^{t h}

n^{t h}

a_{n} = \frac{n^{2}}{2^{n}}

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program