Find the integral of the given function w.r.t x

$y = s i n 6 x + 10 s e c^{2} x - c o s e c x c o t x$

$6 c o s 6 x + 20 s e c^{2} x t a n x + c o s e c x c o t x + c o s e c^{3} x + c$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$c o s 6 x + 10 t a n x + c o s e c x + c$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$- \frac{c o s (6 x)}{6} + 10 t a n x - (c o s e c x) + c$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$- c o s e c 6 x + 10 t a n x + c o s e c x + c$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$- \frac{c o s (6 x)}{6} + 10 t a n x - (c o s e c x) + c$

$y = s i n 6 x + 10 s e c^{2} x - c o s e c x c o t x$

$\Rightarrow \int (s i n 6 x + 10 s e c^{2} x - c o s e c x c o t x) d x$

$\Rightarrow \int (s i n 6 x) d x + \int (10 s e c^{2} x) d x - \int (c o s e c x c o t x) d x$

$6 x = t \Rightarrow 6 d x = d t \Rightarrow d x = \frac{d t}{6}$

$\Rightarrow \int \frac{(s i n t) d t}{6} + 10 t a n x + c_{1} - (- c o s e c x) + c_{2}$

$\Rightarrow \frac{- c o s (t)}{6} + c_{o} + 10 t a n x + c_{1} + c o s e c x + c_{2}$

$\Rightarrow \frac{- c o s 6 x}{6} + 10 t a n x + c o s e c x + c$

Suggest Corrections

Similar questions

Find the integral of the given function w.r.t x

$y = c o s (8 x + 6) + c o s e c^{2} (7 x + 5) + 6 s e c x t a n x$

Find the integral of the given function w.r.t x

$y = s i n 6 x + 10 s e c^{2} x - c o s e c x c o t x$

Find the integral of the given function w.r.t x

$y = s i n (8 x) + x$

Find the integral of the given function w.r.t - x

$y = \frac{s i n^{2} \sqrt{x}}{2 \sqrt{x}}$

Find the Integral of the given function w.r.t x

$Y = 3 x^{2} - \frac{1}{\sqrt{x}}$

Join BYJU'S Learning Program