Find the intercepts cut off by the plane

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Solution

Dividing both sides of equation (1) by 5, we obtain

It is known that the equation of a plane in intercept form is , where a, b, c are the intercepts cut off by the plane at x, y, and z axes respectively.

Therefore, for the given equation,

Thus, the intercepts cut off by the plane are.

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Similar questions

Find the intercepts cut-off by the plane 2x+y-z=5.

2 x + y - z = 5

2 x + y - 2 z = 5

\to r . (2^i +^j -^k) - 5 = 0

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