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Question

find the inverse of A using elementary transformations where A=[1 3 -2 -3 0 -5 2 5 0]

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Solution

Dear Student,

Write the augmented matrix

â„– A1 A2 A3 A1 A2 A3
1 1 3 -2 1 0 0
2 -3 0 -5 0 1 0
3 2 5 0 0 0 1

Find the pivot in the 1st column in the 1st row

â„– A1 A2 A3 A1 A2 A3
1 1 3 -2 1 0 0
2 -3 0 -5 0 1 0
3 2 5 0 0 0 1

Multiply the 1st row by -3

â„– A1 A2 A3 A1 A2 A3
1 -3 -9 6 -3 0 0
2 -3 0 -5 0 1 0
3 2 5 0 0 0 1

Subtract the 1st row from the 2nd row and restore it

â„– A1 A2 A3 A1 A2 A3
1 1 3 -2 1 0 0
2 0 9 -11 3 1 0
3 2 5 0 0 0 1

Multiply the 1st row by 2

â„– A1 A2 A3 A1 A2 A3
1 2 6 -4 2 0 0
2 0 9 -11 3 1 0
3 2 5 0 0 0 1

Subtract the 1st row from the 3rd row and restore it

â„– A1 A2 A3 A1 A2 A3
1 1 3 -2 1 0 0
2 0 9 -11 3 1 0
3 0 -1 4 -2 0 1

Find the pivot in the 2nd column (inversing the sign in the whole row) and swap the 3rd and the 2nd rows

â„– A1 A2 A3 A1 A2 A3
1 1 3 -2 1 0 0
2 0 1 -4 2 0 -1
3 0 9 -11 3 1 0

Multiply the 2nd row by 3

â„– A1 A2 A3 A1 A2 A3
1 1 3 -2 1 0 0
2 0 3 -12 6 0 -3
3 0 9 -11 3 1 0

Subtract the 2nd row from the 1st row and restore it

â„– A1 A2 A3 A1 A2 A3
1 1 0 10 -5 0 3
2 0 1 -4 2 0 -1
3 0 9 -11 3 1 0

Multiply the 2nd row by 9

â„– A1 A2 A3 A1 A2 A3
1 1 0 10 -5 0 3
2 0 9 -36 18 0 -9
3 0 9 -11 3 1 0

Subtract the 2nd row from the 3rd row and restore it

â„– A1 A2 A3 A1 A2 A3
1 1 0 10 -5 0 3
2 0 1 -4 2 0 -1
3 0 0 25 -15 1 9

Make the pivot in the 3rd column by dividing the 3rd row by 25

â„– A1 A2 A3 A1 A2 A3
1 1 0 10 -5 0 3
2 0 1 -4 2 0 -1
3 0 0 1 -3/5 1/25 9/25

Multiply the 3rd row by 10

â„– A1 A2 A3 A1 A2 A3
1 1 0 10 -5 0 3
2 0 1 -4 2 0 -1
3 0 0 10 -6 2/5 18/5

Subtract the 3rd row from the 1st row and restore it

â„– A1 A2 A3 A1 A2 A3
1 1 0 0 1 -2/5 -3/5
2 0 1 -4 2 0 -1
3 0 0 1 -3/5 1/25 9/25

Multiply the 3rd row by -4

â„– A1 A2 A3 A1 A2 A3
1 1 0 0 1 -2/5 -3/5
2 0 1 -4 2 0 -1
3 0 0 -4 12/5 -4/25 -36/25

Subtract the 3rd row from the 2nd row and restore it

â„– A1 A2 A3 A1 A2 A3
1 1 0 0 1 -2/5 -3/5
2 0 1 0 -2/5 4/25 11/25
3 0 0 1 -3/5 1/25 9/25

There is the inverse matrix on the right

â„– A1 A2 A3 A1 A2 A3
1 1 0 0 1 -2/5 -3/5
2 0 1 0 -2/5 4/25 11/25
3 0 0 1 -3/5 1/25 9/25

Result:

â„– A1 A2 A3
1 1 -2/5 -3/5
2 -2/5 4/25 11/25
3 -3/5 1/25 9/25

Regards

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