Question

Find the largest number that will divide 398 , 436 and 542 leaving remainders 7 , 11 and 15 respectively.

Answer 1

We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively. Hence, we need to find the HCF of three numbers (398-7), (436-11) and (542-15).

Hence,
398 - 7 = 391
436 - 11 = 425
542 - 15 = 527
Now, you can find the HCF(391, 425, 527) = 17

Hence, the largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is 17.