Question

The largest positive integer that will divide 398 436 and 542 leaving remainder 7 11 and 15 respectively

Answer 1

We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively. Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,
398 - 7 = 391
436 - 11 = 425
542 - 15 = 527

Now, you can find the hcf(391, 425, 527) = 17

Hence, the largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is 17.