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Question

Find the largest positive integer that will divisible 122, 150 and 115 leaving remainder 5, 7 and 11 respectively.

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Solution

1225=117
1507=143
11511=104

The HCF of 104,117 and 143 is 13

The largest number which divides 122,150 and 115 leaving 5,7and 11 respectively as remainders is 13

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