Question

Find the last 2 digits of the following number:
$65\times 29\times 37\times 63\times 71\times 87\times 85$

• A. 25
• B. 35
• C. 75
• D. 85

Answer 1

The correct option is C 75

$\frac{[65\times 29\times 37\times 63\times 71\times 87\times 85]}{100}\to \frac{[-35\times 29\times 37\times -37\times -29\times -13\times -15]}{100}\to \frac{[35\times 29\times 37\times 37\times 29\times 13\times -15]}{100}=\frac{[1015\times 1369\times 377\times -15]}{100}\to \frac{[15\times 69\times 77\times -15]}{100}\to$ remainder as 75.