Question

Find the least fraction, which must be multiplied to $(1\frac{2}{4}-\frac{1}{2}+3\frac{6}{16}-\frac{1}{16}+\frac{2}{8})$ to make it an integer.

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Given, $(1\frac{2}{4}-\frac{1}{2}+3\frac{6}{16}-\frac{1}{16}+\frac{2}{8})$

= $\frac{6}{4}-\frac{1}{2}+\frac{54}{16}-\frac{1}{16}+\frac{2}{8}$
[Any mixed fraction a$\frac{b}{c}$ can be written as $\frac{ac\times b}{c}$]

Taking LCM of denominators and solving,
$\frac{24-8+54-1+4}{16}$ = $\frac{73}{16}$ [LCM of 4, 2, 16, and 8 is 16]

Now, if we multiply $\frac{73}{16}$ by $\frac{16}{1}$, it becomes 73, which is an integer.
Hence, $\frac{16}{1}$ is the required fraction.