Question

Find the least number which when divided by $12,16,24$ and $36$ leaves a remainder $7$ in each case.

Answer 1

The least number which is divisible by each of $12,16,24,$ and $36$ is LCM of $16,22,40$

$⟹$ LCM is $144$

Now, Required Number $=144+7=151$

$\therefore 151$ is the least number which when divided by $12,16,24$ and $36$ leaves the remainder $7$ in each case.