Find the least number which when divided by 12, leaves a remainder of 7, when divided by 15, leaves a remainder of 10 and when divided by 16, leaves a remainder of 11.

115

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235

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475

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247

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Solution

The correct option is B
235

$12 - 7 = 5$
$15 - 10 = 5$
$16 - 11 = 5$
Hence, the desired number is 5 less than the L.C.M of 12, 15 and 16.
L.C.M of 12, 15 and 16 is 240.
Hence, the least number $= 240 - 5 = 235$

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(ANS given :235)

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Find the least number which when divided by 12, leaves a remainder of 7, when divided by 15, leaves a remainder of 10 and when divided by 16, leaves a remainder of 11.

The correct option is B 235 12−7=5 15−10=5 16−11=5 Hence, the desired number is 5 less than the L.C.M of 12, 15 and 16. L.C.M of 12, 15 and 16 is 240. Hence, the least number=240−5=235

The correct option is B
235

$12 - 7 = 5$
$15 - 10 = 5$
$16 - 11 = 5$
Hence, the desired number is 5 less than the L.C.M of 12, 15 and 16.
L.C.M of 12, 15 and 16 is 240.
Hence, the least number $= 240 - 5 = 235$