Find the least number which when divided by 15, 21, 24 and 32 leaves the same remainder 2 in each case.

3362

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3360

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3456

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3266

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3364

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Solution

The correct option is A 3362
It will be the LCM of these numbers +2
So 3360+2 is the required answer.

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