Question

Find the least number which when divided by $36,48$ and $112$ ; leaves no remainder.

Answer 1

This means, we need to find the LCM of the numbers
First we write all numbers as product of their prime numbers.
$36=2\times 2\times 3\times 3$
$48=2\times 2\times 2\times 2\times 3$
$112=2\times 2\times 2\times 2\times 7$
We then choose each prime number with the greatest power and multiply them to get the LCM.

$\therefore LCM=2\times 2\times 2\times 2\times 3\times 3\times 7=1008$