Find the length of a rectangle, which has:
$a r e a = 768 m^{2}$ and $b r e a d t h = 24 m$

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Solution

Let the length of the rectangle $= l$ m
Area of the rectangle $= l \times b = 768 m^{2}$
$24 l = 768 => l = 32 m$

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Find the length of a rectangle, which has:area=768m2 and breadth=24m

Let the length of the rectangle =l m Area of the rectangle =l×b=768m224l=768=>l=32m

Find the length of a rectangle, which has:
$a r e a = 768 m^{2}$ and $b r e a d t h = 24 m$

Let the length of the rectangle $= l$ m
Area of the rectangle $= l \times b = 768 m^{2}$
$24 l = 768 => l = 32 m$