Question

In the given figure, ABCD is a rectangle with length = 36 m and breadth = 24 m. In ∆ADE, EF ⊥ AD and EF = 15 m. Calculate the area of the shaded region.

Answer 1

Area of the rectangle = AB $\times$ BC
= 36 m $\times$ 24 m
= 864 m²
Area of the triangle = $\frac{1}{2}$ $\times$ AD $\times$ FE
= $\frac{1}{2}$ $\times$ BC $\times$ FE [since AD = BC]
= $\frac{1}{2}$ $\times$ 24 m $\times$ 15 m
= 12 m $\times$15 m = 180 m²
∴ Area of the shaded region = Area of the rectangle − Area of the triangle
= (864 − 180) m²
= 684 m²