Question

In Fig 31, ABCD is a rectangle with dimensions 32 m by 18 m. ADE is a triangle such that EF ⊥ AD and EF = 14 cm. Calculate the area of the shaded region.

Answer 1

We have,
Area of the rectangle = AB x BC
= 32 m x 18 m
= 576 m²
Area of the triangle = $\frac{1}{2}$x AD x FE
= $\frac{1}{2}$x BC x FE [Since AD = BC]
= $\frac{1}{2}$x 18 m x 14 m
= 9 m x 14 m = 126 m²
∴ Area of the shaded region = Area of the rectangle − Area of the triangle
=(576 − 126) m²
= 450 m²