Find the length of each side of a square whose area is equal to the area of a rectangle of length 13.6 metres and breadth 3.4 metres.

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Solution

Length of rectangle(l)=13.6 m
and width(b)= 3.4 m
$∴$ Area= $l \times b = 13.6 \times 3.4 m^{2}$
$= 46.24 m^{2}$
Now, area of square = a
$∴ a^{2} = 46.24 m^{2}$
$\Rightarrow a = \sqrt{46.24} m = 6.8 m$

Hence, side of square= 6.8m

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Find the length of each side of a square whose area is equal to the area of a rectangle of length 13.6 metres and breadth 3.4 metres.

Length of rectangle(l)=13.6 m and width(b)= 3.4 m ∴ Area= l×b=13.6×3.4m2 =46.24m2 Now, area of square = a ∴a2=46.24m2 ⇒a=√46.24m=6.8m Hence, side of square= 6.8m

Length of rectangle(l)=13.6 m
and width(b)= 3.4 m
$∴$ Area= $l \times b = 13.6 \times 3.4 m^{2}$
$= 46.24 m^{2}$
Now, area of square = a
$∴ a^{2} = 46.24 m^{2}$
$\Rightarrow a = \sqrt{46.24} m = 6.8 m$

Hence, side of square= 6.8m