Find the length of EF, if AB =5cm and CA= 7cm, given that AD is the line of symmetry for the figure.

1 cm

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2 cm

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3 cm

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1.5 cm

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Solution

The correct option is B 2 cm
Since AD is the line of symmetry, the part of the figure to the right of this line is the reflection of the part of the figure to the left of it.

$∴ A B = A E = 5 c m and C A = F A = 7 c m .$
Hence,
$E F = F A - A E$
$E F = 7 - 5 = 2 c m$

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Find the length of EF, if AB =5cm and CA= 7cm, given that AD is the line of symmetry for the figure.

The correct option is B 2 cmSince AD is the line of symmetry, the part of the figure to the right of this line is the reflection of the part of the figure to the left of it. ∴AB=AE=5cm and CA=FA=7 cm. Hence, EF=FA−AE EF=7−5=2 cm

The correct option is B 2 cm
Since AD is the line of symmetry, the part of the figure to the right of this line is the reflection of the part of the figure to the left of it.

$∴ A B = A E = 5 c m and C A = F A = 7 c m .$
Hence,
$E F = F A - A E$
$E F = 7 - 5 = 2 c m$