Find the length of the canvas $2$ m in width required to make a conical tent $12$ m in diameter and $63$ m in slant height?

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Solution

Diameter of the cone $= 12 m$
radius of the cone $= 6 m$
Slant height of the cone $= 63 m$
Therefore $,$
Area of the canvas used $=$ area of the cone $= π r \sqrt{h^{2} + r^{2}}$
$= π 6 (\sqrt{3969 + 36}) = 1192.9 m^{2}$
Now,
width of the canvas $= 2 m$
Area of the canvas $= 1192.9 m^{2}$
$L \times 2 = 1192.9$
$L = 596.45 m$
Now
Cost of $1 m$ canvas $= 15 r s$
Cost of $596.45 m$ canvas $= 15 \times 596.45 = 8946.45 r s$

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Find the length of the canvas 2m in width required to make a conical tent 12m in diameter and 63m in slant height?

Find the length of the canvas $2$ m in width required to make a conical tent $12$ m in diameter and $63$ m in slant height?