Find the length of the longest rod that can be put in a hall dimension $23 m \times 10 m \times 10 m$ .

Open in App

Solution

Length = 23m
breadth = 10m
height = 10m
diagonal = longest rod
diagonal = √ l²+b²+c²
√ (23)²+(10)²+(10)²
√ 529+100+100
√ 729
= 27 m
so longest rod that can be put in a hall = 27 m

Suggest Corrections

Similar questions

23 m \times 10 m \times 10 m

The length of the longest rod that can be put in a hall of dimension 23 m x 10m x 10 m is:

10 m \times 10 m \times 5 m

The length of the longest rod that can be placed in a room of dimensions $(10 m \times 10 m \times 5 m)$

(a) 15 m (b) 16 m (c) $\sqrt{5} m$ (d) 12 m

Join BYJU'S Learning Program