Question

The length of the longest rod that can be placed in a room of dimensions $(10m\times 10m\times 5m)$

(a) 15 m (b) 16 m (c) $\sqrt{5}m$ (d) 12 m

Answer 1

ANSWER: (a) 15 m

Length of longest rod = diagonal of the room = diagonal of a cuboid = $\sqrt{l^2+b^2+h^2}=\sqrt{100+100+25}=\sqrt{225}m$= 15 m