Question

Question 9
The length of the longest pole that can be put in a room of dimensions $(10m\times 10m\times 5m)$ is:

A) 15 m
B) 16 m
C) 10 m
D) 12 m

Answer 1

The answer is A.
Given, dimensions of a room;
l = 10m, b = 10m, h = 5m

$\therefore$ Length of the longest pole = Diagonal of the cuboid (room)

$=\sqrt{l^2+b^2+h^2}$

$=\sqrt{(10{)}^2+(10{)}^2+(5{)}^2}$

$=\sqrt{100+100+25}$

$=\sqrt{225}=15m$

Hence, the length of the longest pole is 15 m.