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Question

Find the locus of the points of intersection of two tangents to a hyperbola x2a2y2b2=1, if sum of their slopes is a constant =λ.

A
(λx2a2)=2xy
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B
λ(x2a2)=2xy
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C
(x2λa2)=2xy
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D
None of these
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Solution

The correct option is B λ(x2a2)=2xy
Any tangent to hyperbola is
y=mx+a2m2b2
If it passes through the point (h,k), then
(kmh)2=a2m2b2
or m2(h2a2)2mhk+k2+b2=0 ...(1)
Then there will be two tangents passing through (h,k) whose slopes are given by (1)
Now m1+m2=λ2hkh2a2=λ
Locus is λ(x2a2)=2xy

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