Find the magnitude & direction of frictional force between block A and table, if block A is pulled towards left with a force of 50N.
A
10^i
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B
10^j
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C
20^i
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D
20^j
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Solution
The correct option is A10^i Maximum possible frictional force on block A , f=μN=μmg=0.8(5)(10)=40N...(i) Considering frictional force is sufficient to prevent movement of blocks i.e. a=0 writing equilibrium equation for block A 50−f−T=0...(ii) where f is friction force and T is the tension in the rope. Writing equilibrium equation for block B T=4g=40N...(iii) using equation (ii) and (iii) ⇒f=1g=10N the frictional force value is less than the maximum limit of friction force hence the system is in static condition.